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5x^2=6/10
We move all terms to the left:
5x^2-(6/10)=0
We add all the numbers together, and all the variables
5x^2-(+6/10)=0
We get rid of parentheses
5x^2-6/10=0
We multiply all the terms by the denominator
5x^2*10-6=0
Wy multiply elements
50x^2-6=0
a = 50; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·50·(-6)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*50}=\frac{0-20\sqrt{3}}{100} =-\frac{20\sqrt{3}}{100} =-\frac{\sqrt{3}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*50}=\frac{0+20\sqrt{3}}{100} =\frac{20\sqrt{3}}{100} =\frac{\sqrt{3}}{5} $
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